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q�dS (� ar "Executable documentation" for the pickle module.
Extensive comments about the pickle protocols and pickle-machine opcodes
can be found here. Some functions meant for external use:
genops(pickle)
Generate all the opcodes in a pickle, as (opcode, arg, position) triples.
dis(pickle, out=None, memo=None, indentlevel=4)
Print a symbolic disassembly of a pickle.
� N�dis�genops�optimize�������������������������c @ s e Zd ZdZdd� ZdS )�ArgumentDescriptor��name�n�reader�docc C s || _ || _|| _|| _d S �Nr )�selfr r
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>>> import io
>>> read_uint1(io.BytesIO(b'\xff'))
255
� r z'not enough data in stream to read uint1N)�read�
ValueError��f�datar r r �
read_uint1� s
r! �uint1r zOne-byte unsigned integer.r c C s0 | � d�}t|�dkr$td|�d S td��dS )z�
>>> import io
>>> read_uint2(io.BytesIO(b'\xff\x00'))
255
>>> read_uint2(io.BytesIO(b'\xff\xff'))
65535
� z
>> import io
>>> read_int4(io.BytesIO(b'\xff\x00\x00\x00'))
255
>>> read_int4(io.BytesIO(b'\x00\x00\x00\x80')) == -(2**31)
True
� z>> import io
>>> read_uint4(io.BytesIO(b'\xff\x00\x00\x00'))
255
>>> read_uint4(io.BytesIO(b'\x00\x00\x00\x80')) == 2**31
True
r) z>> import io
>>> read_uint8(io.BytesIO(b'\xff\x00\x00\x00\x00\x00\x00\x00'))
255
>>> read_uint8(io.BytesIO(b'\xff' * 8)) == 2**64-1
True
� z>> import io
>>> read_stringnl(io.BytesIO(b"'abcd'\nefg\n"))
'abcd'
>>> read_stringnl(io.BytesIO(b"\n"))
Traceback (most recent call last):
...
ValueError: no string quotes around b''
>>> read_stringnl(io.BytesIO(b"\n"), stripquotes=False)
''
>>> read_stringnl(io.BytesIO(b"''\n"))
''
>>> read_stringnl(io.BytesIO(b'"abcd"'))
Traceback (most recent call last):
...
ValueError: no newline found when trying to read stringnl
Embedded escapes are undone in the result.
>>> read_stringnl(io.BytesIO(br"'a\n\\b\x00c\td'" + b"\n'e'"))
'a\n\\b\x00c\td'
�
z-no newline found when trying to read stringnlNr )� "� 'z,strinq quote %r not found at both ends of %rr zno string quotes around %rr �ascii)�readline�endswithr �
startswith�codecs�
escape_decode�decode)r r: � stripquotesr �qr r r �
read_stringnl; s"
� r= �stringnlz�A newline-terminated string.
This is a repr-style string, with embedded escapes, and
bracketing quotes.
c C s t | dd�S )NF)r; )r= �r r r r �read_stringnl_noescapet s r@ �stringnl_noescapea A newline-terminated string.
This is a str-style string, without embedded escapes,
or bracketing quotes. It should consist solely of
printable ASCII characters.
c C s dt | �t | �f S )zp
>>> import io
>>> read_stringnl_noescape_pair(io.BytesIO(b"Queue\nEmpty\njunk"))
'Queue Empty'
z%s %s)r@ r? r r r �read_stringnl_noescape_pair� s rB �stringnl_noescape_paira� A pair of newline-terminated strings.
These are str-style strings, without embedded
escapes, or bracketing quotes. They should
consist solely of printable ASCII characters.
The pair is returned as a single string, with
a single blank separating the two strings.
c C s@ t | �}| �|�}t|�|kr(|�d�S td|t|�f ��dS )z�
>>> import io
>>> read_string1(io.BytesIO(b"\x00"))
''
>>> read_string1(io.BytesIO(b"\x03abcdef"))
'abc'
�latin-1z2expected %d bytes in a string1, but only %d remainN)r! r r% r: r �r r
r r r r � read_string1� s
�rF �string1z�A counted string.
The first argument is a 1-byte unsigned int giving the number
of bytes in the string, and the second argument is that many
bytes.
c C sT t | �}|dk r td| ��| �|�}t|�|kr<|�d�S td|t|�f ��dS )aP
>>> import io
>>> read_string4(io.BytesIO(b"\x00\x00\x00\x00abc"))
''
>>> read_string4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
'abc'
>>> read_string4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
Traceback (most recent call last):
...
ValueError: expected 50331648 bytes in a string4, but only 6 remain
r zstring4 byte count < 0: %drD z2expected %d bytes in a string4, but only %d remainN)r* r r r% r: rE r r r � read_string4� s
�rH �string4z�A counted string.
The first argument is a 4-byte little-endian signed int giving
the number of bytes in the string, and the second argument is
that many bytes.
c C s: t | �}| �|�}t|�|kr"|S td|t|�f ��dS )z�
>>> import io
>>> read_bytes1(io.BytesIO(b"\x00"))
b''
>>> read_bytes1(io.BytesIO(b"\x03abcdef"))
b'abc'
z1expected %d bytes in a bytes1, but only %d remainN)r! r r% r rE r r r � read_bytes1� s
�rJ �bytes1z�A counted bytes string.
The first argument is a 1-byte unsigned int giving the number
of bytes, and the second argument is that many bytes.
c C sP t | �}|tjkr td| ��| �|�}t|�|kr8|S td|t|�f ��dS )aN
>>> import io
>>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x00abc"))
b''
>>> read_bytes4(io.BytesIO(b"\x03\x00\x00\x00abcdef"))
b'abc'
>>> read_bytes4(io.BytesIO(b"\x00\x00\x00\x03abcdef"))
Traceback (most recent call last):
...
ValueError: expected 50331648 bytes in a bytes4, but only 6 remain
z#bytes4 byte count > sys.maxsize: %dz1expected %d bytes in a bytes4, but only %d remainN)r, �sys�maxsizer r r% rE r r r � read_bytes4� s
�rN �bytes4z�A counted bytes string.
The first argument is a 4-byte little-endian unsigned int giving
the number of bytes, and the second argument is that many bytes.
c C sP t | �}|tjkr td| ��| �|�}t|�|kr8|S td|t|�f ��dS )a�
>>> import io, struct, sys
>>> read_bytes8(io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00abc"))
b''
>>> read_bytes8(io.BytesIO(b"\x03\x00\x00\x00\x00\x00\x00\x00abcdef"))
b'abc'
>>> bigsize8 = struct.pack(">> read_bytes8(io.BytesIO(bigsize8 + b"abcdef")) #doctest: +ELLIPSIS
Traceback (most recent call last):
...
ValueError: expected ... bytes in a bytes8, but only 6 remain
z#bytes8 byte count > sys.maxsize: %dz1expected %d bytes in a bytes8, but only %d remainN)r/ rL rM r r r% rE r r r � read_bytes8 s
�rP �bytes8z�A counted bytes string.
The first argument is an 8-byte little-endian unsigned int giving
the number of bytes, and the second argument is that many bytes.
c C sT t | �}|tjkr td| ��| �|�}t|�|kr>> import io, struct, sys
>>> read_bytearray8(io.BytesIO(b"\x00\x00\x00\x00\x00\x00\x00\x00abc"))
bytearray(b'')
>>> read_bytearray8(io.BytesIO(b"\x03\x00\x00\x00\x00\x00\x00\x00abcdef"))
bytearray(b'abc')
>>> bigsize8 = struct.pack(">> read_bytearray8(io.BytesIO(bigsize8 + b"abcdef")) #doctest: +ELLIPSIS
Traceback (most recent call last):
...
ValueError: expected ... bytes in a bytearray8, but only 6 remain
z'bytearray8 byte count > sys.maxsize: %dz5expected %d bytes in a bytearray8, but only %d remainN)r/ rL rM r r r% � bytearrayrE r r r �read_bytearray89 s
�rS �
bytearray8z�A counted bytearray.
The first argument is an 8-byte little-endian unsigned int giving
the number of bytes, and the second argument is that many bytes.
c C s0 | � � }|�d�std��|dd� }t|d�S )zm
>>> import io
>>> read_unicodestringnl(io.BytesIO(b"abc\\uabcd\njunk")) == 'abc\uabcd'
True
r1 z4no newline found when trying to read unicodestringnlNr zraw-unicode-escape)r5 r6 r �strr r r r �read_unicodestringnl[ s
rV �unicodestringnlz�A newline-terminated Unicode string.
This is raw-unicode-escape encoded, so consists of
printable ASCII characters, and may contain embedded
escape sequences.
c C sB t | �}| �|�}t|�|kr*t|dd�S td|t|�f ��dS )a�
>>> import io
>>> s = 'abcd\uabcd'
>>> enc = s.encode('utf-8')
>>> enc
b'abcd\xea\xaf\x8d'
>>> n = bytes([len(enc)]) # little-endian 1-byte length
>>> t = read_unicodestring1(io.BytesIO(n + enc + b'junk'))
>>> s == t
True
>>> read_unicodestring1(io.BytesIO(n + enc[:-1]))
Traceback (most recent call last):
...
ValueError: expected 7 bytes in a unicodestring1, but only 6 remain
�utf-8�
surrogatepassz9expected %d bytes in a unicodestring1, but only %d remainN)r! r r% rU r rE r r r �read_unicodestring1u s
�rZ �unicodestring1aA A counted Unicode string.
The first argument is a 1-byte little-endian signed int
giving the number of bytes in the string, and the second
argument-- the UTF-8 encoding of the Unicode string --
contains that many bytes.
c C sX t | �}|tjkr td| ��| �|�}t|�|kr@t|dd�S td|t|�f ��dS )a�
>>> import io
>>> s = 'abcd\uabcd'
>>> enc = s.encode('utf-8')
>>> enc
b'abcd\xea\xaf\x8d'
>>> n = bytes([len(enc), 0, 0, 0]) # little-endian 4-byte length
>>> t = read_unicodestring4(io.BytesIO(n + enc + b'junk'))
>>> s == t
True
>>> read_unicodestring4(io.BytesIO(n + enc[:-1]))
Traceback (most recent call last):
...
ValueError: expected 7 bytes in a unicodestring4, but only 6 remain
z+unicodestring4 byte count > sys.maxsize: %drX rY z9expected %d bytes in a unicodestring4, but only %d remainN)r, rL rM r r r% rU rE r r r �read_unicodestring4� s
�r\ �unicodestring4aA A counted Unicode string.
The first argument is a 4-byte little-endian signed int
giving the number of bytes in the string, and the second
argument-- the UTF-8 encoding of the Unicode string --
contains that many bytes.
c C sX t | �}|tjkr td| ��| �|�}t|�|kr@t|dd�S td|t|�f ��dS )a�
>>> import io
>>> s = 'abcd\uabcd'
>>> enc = s.encode('utf-8')
>>> enc
b'abcd\xea\xaf\x8d'
>>> n = bytes([len(enc)]) + b'\0' * 7 # little-endian 8-byte length
>>> t = read_unicodestring8(io.BytesIO(n + enc + b'junk'))
>>> s == t
True
>>> read_unicodestring8(io.BytesIO(n + enc[:-1]))
Traceback (most recent call last):
...
ValueError: expected 7 bytes in a unicodestring8, but only 6 remain
z+unicodestring8 byte count > sys.maxsize: %drX rY z9expected %d bytes in a unicodestring8, but only %d remainN)r/ rL rM r r r% rU rE r r r �read_unicodestring8� s
�r^ �unicodestring8aB A counted Unicode string.
The first argument is an 8-byte little-endian signed int
giving the number of bytes in the string, and the second
argument-- the UTF-8 encoding of the Unicode string --
contains that many bytes.
c C s. t | ddd�}|dkrdS |dkr&dS t|�S )z�
>>> import io
>>> read_decimalnl_short(io.BytesIO(b"1234\n56"))
1234
>>> read_decimalnl_short(io.BytesIO(b"1234L\n56"))
Traceback (most recent call last):
...
ValueError: invalid literal for int() with base 10: b'1234L'
F�r: r; s 00s 01T�r= �int�r �sr r r �read_decimalnl_short� s re c C s2 t | ddd�}|dd� dkr*|dd� }t|�S )z�
>>> import io
>>> read_decimalnl_long(io.BytesIO(b"1234L\n56"))
1234
>>> read_decimalnl_long(io.BytesIO(b"123456789012345678901234L\n6"))
123456789012345678901234
Fr` r N� Lra rc r r r �read_decimalnl_long s rg �decimalnl_shorta� A newline-terminated decimal integer literal.
This never has a trailing 'L', and the integer fit
in a short Python int on the box where the pickle
was written -- but there's no guarantee it will fit
in a short Python int on the box where the pickle
is read.
�decimalnl_longz�A newline-terminated decimal integer literal.
This has a trailing 'L', and can represent integers
of any size.
c C s t | ddd�}t|�S )zO
>>> import io
>>> read_floatnl(io.BytesIO(b"-1.25\n6"))
-1.25
Fr` )r= �floatrc r r r � read_floatnl- s rk �floatnla� A newline-terminated decimal floating literal.
In general this requires 17 significant digits for roundtrip
identity, and pickling then unpickling infinities, NaNs, and
minus zero doesn't work across boxes, or on some boxes even
on itself (e.g., Windows can't read the strings it produces
for infinities or NaNs).
c C s0 | � d�}t|�dkr$td|�d S td��dS )z�
>>> import io, struct
>>> raw = struct.pack(">d", -1.25)
>>> raw
b'\xbf\xf4\x00\x00\x00\x00\x00\x00'
>>> read_float8(io.BytesIO(raw + b"\n"))
-1.25
r. z>dr z(not enough data in stream to read float8Nr$ r r r r � read_float8C s
rm �float8a An 8-byte binary representation of a float, big-endian.
The format is unique to Python, and shared with the struct
module (format string '>d') "in theory" (the struct and pickle
implementations don't share the code -- they should). It's
strongly related to the IEEE-754 double format, and, in normal
cases, is in fact identical to the big-endian 754 double format.
On other boxes the dynamic range is limited to that of a 754
double, and "add a half and chop" rounding is used to reduce
the precision to 53 bits. However, even on a 754 box,
infinities, NaNs, and minus zero may not be handled correctly
(may not survive roundtrip pickling intact).
)� decode_longc C s. t | �}| �|�}t|�|kr&td��t|�S )a+
>>> import io
>>> read_long1(io.BytesIO(b"\x00"))
0
>>> read_long1(io.BytesIO(b"\x02\xff\x00"))
255
>>> read_long1(io.BytesIO(b"\x02\xff\x7f"))
32767
>>> read_long1(io.BytesIO(b"\x02\x00\xff"))
-256
>>> read_long1(io.BytesIO(b"\x02\x00\x80"))
-32768
z'not enough data in stream to read long1)r! r r% r ro rE r r r �
read_long1i s
rp �long1a A binary long, little-endian, using 1-byte size.
This first reads one byte as an unsigned size, then reads that
many bytes and interprets them as a little-endian 2's-complement long.
If the size is 0, that's taken as a shortcut for the long 0L.
c C sB t | �}|dk r td| ��| �|�}t|�|kr:td��t|�S )ag
>>> import io
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\xff\x00"))
255
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\xff\x7f"))
32767
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\x00\xff"))
-256
>>> read_long4(io.BytesIO(b"\x02\x00\x00\x00\x00\x80"))
-32768
>>> read_long1(io.BytesIO(b"\x00\x00\x00\x00"))
0
r zlong4 byte count < 0: %dz'not enough data in stream to read long4)r* r r r% ro rE r r r �
read_long4� s
rr �long4a� A binary representation of a long, little-endian.
This first reads four bytes as a signed size (but requires the
size to be >= 0), then reads that many bytes and interprets them
as a little-endian 2's-complement long. If the size is 0, that's taken
as a shortcut for the int 0, although LONG1 should really be used
then instead (and in any case where # of bytes < 256).
c @ s e Zd ZdZdd� Zdd� ZdS )� StackObject�r �obtyper c C s* || _ t|t�r|D ]}q|| _|| _d S r )r �
isinstance�tuplerv r )r r rv r Z containedr r r r � s
zStackObject.__init__c C s | j S r �r )r r r r �__repr__� s zStackObject.__repr__N)r r r r r rz r r r r rt � s
rt rb zA Python integer object.ru Z int_or_boolz#A Python integer or boolean object.�boolzA Python boolean object.rj zA Python float object.Z bytes_or_strz*A Python bytes or (Unicode) string object.�byteszA Python bytes object.rR zA Python bytearray object.rU z!A Python (Unicode) string object.�NonezThe Python None object.rx zA Python tuple object.�listzA Python list object.�dictzA Python dict object.�setzA Python set object.� frozensetzA Python frozenset object.�bufferz A Python buffer-like object.�anyz Any kind of object whatsoever.Zmarkaz 'The mark' is a unique object.
Opcodes that operate on a variable number of objects
generally don't embed the count of objects in the opcode,
or pull it off the stack. Instead the MARK opcode is used
to push a special marker object on the stack, and then
some other opcodes grab all the objects from the top of
the stack down to (but not including) the topmost marker
object.
�
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No matter how many object are on the stack after the topmost
markobject, POP_MARK gets rid of all of them (including the
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c @ s e Zd ZdZdd� ZdS )�
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and LONG then is that INT skips a trailing 'L', and produces a short
int whenever possible.
Another difference is due to that, when bool was introduced as a
distinct type in 2.3, builtin names True and False were also added to
2.2.2, mapping to ints 1 and 0. For compatibility in both directions,
True gets pickled as INT + "I01\n", and False as INT + "I00\n".
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unpickling (this is simply due to the nature of decimal->binary
conversion). Proto 2 added linear-time (in C; still quadratic-time
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decoded as bytes object instead.
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encoding given was 'bytes' however, they will be decoded as bytes
object instead.
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on most boxes).
In general, FLOAT cannot be used to transport infinities, NaNs, or
minus zero across boxes (or even on a single box, if the platform C
library can't read the strings it produces for such things -- Windows
is like that), but may do less damage than BINFLOAT on boxes with
greater precision or dynamic range than IEEE-754 double.
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immediately under the topmost markobject. Everything at and after the
topmost markobject is popped, leaving the mutated dict at the top
of the stack.
Stack before: ... pydict markobject key_1 value_1 ... key_n value_n
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The slice of the stack following the topmost markobject is taken as
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leaving the mutated set at the top of the stack.
Stack before: ... pyset markobject item_1 ... item_n
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where pyset has been modified via pyset.add(item_i) = item_i for i in
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�POP�0z.
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Else the argument must be a dict, the object must have a __dict__, and
the object is updated via
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ZINST�iaq Build a class instance.
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INST is followed by two newline-terminated strings, giving a
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is used to get a class object.
In addition, all the objects on the stack following the topmost
markobject are gathered into a tuple and popped (along with the
topmost markobject), just as for the TUPLE opcode.
Now it gets complicated. If all of these are true:
+ The argtuple is empty (markobject was at the top of the stack
at the start).
+ The class object does not have a __getinitargs__ attribute.
then we want to create an old-style class instance without invoking
its __init__() method (pickle has waffled on this over the years; not
calling __init__() is current wisdom). In this case, an instance of
an old-style dummy class is created, and then we try to rebind its
__class__ attribute to the desired class object. If this succeeds,
the new instance object is pushed on the stack, and we're done.
Else (the argtuple is not empty, it's not an old-style class object,
or the class object does have a __getinitargs__ attribute), the code
first insists that the class object have a __safe_for_unpickling__
attribute. Unlike as for the __safe_for_unpickling__ check in REDUCE,
it doesn't matter whether this attribute has a true or false value, it
only matters whether it exists (XXX this is a bug). If
__safe_for_unpickling__ doesn't exist, UnpicklingError is raised.
Else (the class object does have a __safe_for_unpickling__ attr),
the class object obtained from INST's arguments is applied to the
argtuple obtained from the stack, and the resulting instance object
is pushed on the stack.
NOTE: checks for __safe_for_unpickling__ went away in Python 2.3.
NOTE: the distinction between old-style and new-style classes does
not make sense in Python 3.
ZOBJ�oa� Build a class instance.
This is the protocol 1 version of protocol 0's INST opcode, and is
very much like it. The major difference is that the class object
is taken off the stack, allowing it to be retrieved from the memo
repeatedly if several instances of the same class are created. This
can be much more efficient (in both time and space) than repeatedly
embedding the module and class names in INST opcodes.
Unlike INST, OBJ takes no arguments from the opcode stream. Instead
the class object is taken off the stack, immediately above the
topmost markobject:
Stack before: ... markobject classobject stackslice
Stack after: ... new_instance_object
As for INST, the remainder of the stack above the markobject is
gathered into an argument tuple, and then the logic seems identical,
except that no __safe_for_unpickling__ check is done (XXX this is
a bug). See INST for the gory details.
NOTE: In Python 2.3, INST and OBJ are identical except for how they
get the class object. That was always the intent; the implementations
had diverged for accidental reasons.
ZNEWOBJ� aL Build an object instance.
The stack before should be thought of as containing a class
object followed by an argument tuple (the tuple being the stack
top). Call these cls and args. They are popped off the stack,
and the value returned by cls.__new__(cls, *args) is pushed back
onto the stack.
Z NEWOBJ_EX� au Build an object instance.
The stack before should be thought of as containing a class
object followed by an argument tuple and by a keyword argument dict
(the dict being the stack top). Call these cls and args. They are
popped off the stack, and the value returned by
cls.__new__(cls, *args, *kwargs) is pushed back onto the stack.
�PROTO� z�Protocol version indicator.
For protocol 2 and above, a pickle must start with this opcode.
The argument is the protocol version, an int in range(2, 256).
ZSTOP�.z�Stop the unpickling machine.
Every pickle ends with this opcode. The object at the top of the stack
is popped, and that's the result of unpickling. The stack should be
empty then.
�FRAME� z�Indicate the beginning of a new frame.
The unpickler may use this opcode to safely prefetch data from its
underlying stream.
ZPERSID�Pa Push an object identified by a persistent ID.
The pickle module doesn't define what a persistent ID means. PERSID's
argument is a newline-terminated str-style (no embedded escapes, no
bracketing quote characters) string, which *is* "the persistent ID".
The unpickler passes this string to self.persistent_load(). Whatever
object that returns is pushed on the stack. There is no implementation
of persistent_load() in Python's unpickler: it must be supplied by an
unpickler subclass.
Z BINPERSID�QaX Push an object identified by a persistent ID.
Like PERSID, except the persistent ID is popped off the stack (instead
of being a string embedded in the opcode bytestream). The persistent
ID is passed to self.persistent_load(), and whatever object that
returns is pushed on the stack. See PERSID for more detail.
z%repeated name %r at indices %d and %dz%repeated code %r at indices %d and %dFc C s t �� }tjD ]�}t�d|�s0| rtd| � qtt|�}t|t �rPt
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'pickle' is a file-like object, or string, containing the pickle.
Each opcode in the pickle is generated, from the current pickle position,
stopping after a STOP opcode is delivered. A triple is generated for
each opcode:
opcode, arg, pos
opcode is an OpcodeInfo record, describing the current opcode.
If the opcode has an argument embedded in the pickle, arg is its decoded
value, as a Python object. If the opcode doesn't have an argument, arg
is None.
If the pickle has a tell() method, pos was the value of pickle.tell()
before reading the current opcode. If the pickle is a bytes object,
it's wrapped in a BytesIO object, and the latter's tell() result is
used. Else (the pickle doesn't have a tell(), and it's not obvious how
to query its current position) pos is None.
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d| ��dS ) aK Produce a symbolic disassembly of a pickle.
'pickle' is a file-like object, or string, containing a (at least one)
pickle. The pickle is disassembled from the current position, through
the first STOP opcode encountered.
Optional arg 'out' is a file-like object to which the disassembly is
printed. It defaults to sys.stdout.
Optional arg 'memo' is a Python dict, used as the pickle's memo. It
may be mutated by dis(), if the pickle contains PUT or BINPUT opcodes.
Passing the same memo object to another dis() call then allows disassembly
to proceed across multiple pickles that were all created by the same
pickler with the same memo. Ordinarily you don't need to worry about this.
Optional arg 'indentlevel' is the number of blanks by which to indent
a new MARK level. It defaults to 4.
Optional arg 'annotate' if nonzero instructs dis() to add short
description of the opcode on each line of disassembled output.
The value given to 'annotate' must be an integer and is used as a
hint for the column where annotation should start. The default
value is 0, meaning no annotations.
In addition to printing the disassembly, some sanity checks are made:
+ All embedded opcode arguments "make sense".
+ Explicit and implicit pop operations have enough items on the stack.
+ When an opcode implicitly refers to a markobject, a markobject is
actually on the stack.
+ A memo entry isn't referenced before it's defined.
+ The markobject isn't stored in the memo.
+ A memo entry isn't redefined.
Nr � z%5d:)�end�filez %-4s %s%sr r� z (MARK at unknown opcode offset)z (MARK at %d)r zno MARK exists on stack)r� r� r� r� r� z(as %d)zmemo key %r already definedz'stack is empty -- can't store into memoz"can't store markobject in the memo)r� r� r� z&memo key %r has never been stored into�
�2 r� )r z3tries to pop %d items from stack with only %d itemsz highest protocol among opcodes =z stack not empty after STOP: %r)r r� �reprr� r% r �maxr� r� r� �
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>>> import pickle
>>> x = [1, 2, (3, 4), {b'abc': "def"}]
>>> pkl0 = pickle.dumps(x, 0)
>>> dis(pkl0)
0: ( MARK
1: l LIST (MARK at 0)
2: p PUT 0
5: I INT 1
8: a APPEND
9: I INT 2
12: a APPEND
13: ( MARK
14: I INT 3
17: I INT 4
20: t TUPLE (MARK at 13)
21: p PUT 1
24: a APPEND
25: ( MARK
26: d DICT (MARK at 25)
27: p PUT 2
30: c GLOBAL '_codecs encode'
46: p PUT 3
49: ( MARK
50: V UNICODE 'abc'
55: p PUT 4
58: V UNICODE 'latin1'
66: p PUT 5
69: t TUPLE (MARK at 49)
70: p PUT 6
73: R REDUCE
74: p PUT 7
77: V UNICODE 'def'
82: p PUT 8
85: s SETITEM
86: a APPEND
87: . STOP
highest protocol among opcodes = 0
Try again with a "binary" pickle.
>>> pkl1 = pickle.dumps(x, 1)
>>> dis(pkl1)
0: ] EMPTY_LIST
1: q BINPUT 0
3: ( MARK
4: K BININT1 1
6: K BININT1 2
8: ( MARK
9: K BININT1 3
11: K BININT1 4
13: t TUPLE (MARK at 8)
14: q BINPUT 1
16: } EMPTY_DICT
17: q BINPUT 2
19: c GLOBAL '_codecs encode'
35: q BINPUT 3
37: ( MARK
38: X BINUNICODE 'abc'
46: q BINPUT 4
48: X BINUNICODE 'latin1'
59: q BINPUT 5
61: t TUPLE (MARK at 37)
62: q BINPUT 6
64: R REDUCE
65: q BINPUT 7
67: X BINUNICODE 'def'
75: q BINPUT 8
77: s SETITEM
78: e APPENDS (MARK at 3)
79: . STOP
highest protocol among opcodes = 1
Exercise the INST/OBJ/BUILD family.
>>> import pickletools
>>> dis(pickle.dumps(pickletools.dis, 0))
0: c GLOBAL 'pickletools dis'
17: p PUT 0
20: . STOP
highest protocol among opcodes = 0
>>> from pickletools import _Example
>>> x = [_Example(42)] * 2
>>> dis(pickle.dumps(x, 0))
0: ( MARK
1: l LIST (MARK at 0)
2: p PUT 0
5: c GLOBAL 'copy_reg _reconstructor'
30: p PUT 1
33: ( MARK
34: c GLOBAL 'pickletools _Example'
56: p PUT 2
59: c GLOBAL '__builtin__ object'
79: p PUT 3
82: N NONE
83: t TUPLE (MARK at 33)
84: p PUT 4
87: R REDUCE
88: p PUT 5
91: ( MARK
92: d DICT (MARK at 91)
93: p PUT 6
96: V UNICODE 'value'
103: p PUT 7
106: I INT 42
110: s SETITEM
111: b BUILD
112: a APPEND
113: g GET 5
116: a APPEND
117: . STOP
highest protocol among opcodes = 0
>>> dis(pickle.dumps(x, 1))
0: ] EMPTY_LIST
1: q BINPUT 0
3: ( MARK
4: c GLOBAL 'copy_reg _reconstructor'
29: q BINPUT 1
31: ( MARK
32: c GLOBAL 'pickletools _Example'
54: q BINPUT 2
56: c GLOBAL '__builtin__ object'
76: q BINPUT 3
78: N NONE
79: t TUPLE (MARK at 31)
80: q BINPUT 4
82: R REDUCE
83: q BINPUT 5
85: } EMPTY_DICT
86: q BINPUT 6
88: X BINUNICODE 'value'
98: q BINPUT 7
100: K BININT1 42
102: s SETITEM
103: b BUILD
104: h BINGET 5
106: e APPENDS (MARK at 3)
107: . STOP
highest protocol among opcodes = 1
Try "the canonical" recursive-object test.
>>> L = []
>>> T = L,
>>> L.append(T)
>>> L[0] is T
True
>>> T[0] is L
True
>>> L[0][0] is L
True
>>> T[0][0] is T
True
>>> dis(pickle.dumps(L, 0))
0: ( MARK
1: l LIST (MARK at 0)
2: p PUT 0
5: ( MARK
6: g GET 0
9: t TUPLE (MARK at 5)
10: p PUT 1
13: a APPEND
14: . STOP
highest protocol among opcodes = 0
>>> dis(pickle.dumps(L, 1))
0: ] EMPTY_LIST
1: q BINPUT 0
3: ( MARK
4: h BINGET 0
6: t TUPLE (MARK at 3)
7: q BINPUT 1
9: a APPEND
10: . STOP
highest protocol among opcodes = 1
Note that, in the protocol 0 pickle of the recursive tuple, the disassembler
has to emulate the stack in order to realize that the POP opcode at 16 gets
rid of the MARK at 0.
>>> dis(pickle.dumps(T, 0))
0: ( MARK
1: ( MARK
2: l LIST (MARK at 1)
3: p PUT 0
6: ( MARK
7: g GET 0
10: t TUPLE (MARK at 6)
11: p PUT 1
14: a APPEND
15: 0 POP
16: 0 POP (MARK at 0)
17: g GET 1
20: . STOP
highest protocol among opcodes = 0
>>> dis(pickle.dumps(T, 1))
0: ( MARK
1: ] EMPTY_LIST
2: q BINPUT 0
4: ( MARK
5: h BINGET 0
7: t TUPLE (MARK at 4)
8: q BINPUT 1
10: a APPEND
11: 1 POP_MARK (MARK at 0)
12: h BINGET 1
14: . STOP
highest protocol among opcodes = 1
Try protocol 2.
>>> dis(pickle.dumps(L, 2))
0: \x80 PROTO 2
2: ] EMPTY_LIST
3: q BINPUT 0
5: h BINGET 0
7: \x85 TUPLE1
8: q BINPUT 1
10: a APPEND
11: . STOP
highest protocol among opcodes = 2
>>> dis(pickle.dumps(T, 2))
0: \x80 PROTO 2
2: ] EMPTY_LIST
3: q BINPUT 0
5: h BINGET 0
7: \x85 TUPLE1
8: q BINPUT 1
10: a APPEND
11: 0 POP
12: h BINGET 1
14: . STOP
highest protocol among opcodes = 2
Try protocol 3 with annotations:
>>> dis(pickle.dumps(T, 3), annotate=1)
0: \x80 PROTO 3 Protocol version indicator.
2: ] EMPTY_LIST Push an empty list.
3: q BINPUT 0 Store the stack top into the memo. The stack is not popped.
5: h BINGET 0 Read an object from the memo and push it on the stack.
7: \x85 TUPLE1 Build a one-tuple out of the topmost item on the stack.
8: q BINPUT 1 Store the stack top into the memo. The stack is not popped.
10: a APPEND Append an object to a list.
11: 0 POP Discard the top stack item, shrinking the stack by one item.
12: h BINGET 1 Read an object from the memo and push it on the stack.
14: . STOP Stop the unpickling machine.
highest protocol among opcodes = 2
a=
>>> import pickle
>>> import io
>>> f = io.BytesIO()
>>> p = pickle.Pickler(f, 2)
>>> x = [1, 2, 3]
>>> p.dump(x)
>>> p.dump(x)
>>> f.seek(0)
0
>>> memo = {}
>>> dis(f, memo=memo)
0: \x80 PROTO 2
2: ] EMPTY_LIST
3: q BINPUT 0
5: ( MARK
6: K BININT1 1
8: K BININT1 2
10: K BININT1 3
12: e APPENDS (MARK at 5)
13: . STOP
highest protocol among opcodes = 2
>>> dis(f, memo=memo)
14: \x80 PROTO 2
16: h BINGET 0
18: . STOP
highest protocol among opcodes = 2
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